How to grep specific line in unix

We can prepend each command with a range parameter that specifies if this command should be applied to specific line or not. "1p" is a first command. It uses p. to print from the second line to the fourth line of (And don't forget to check, sed is a. Is there a nice unix tool to grep the nth line of a file? thanks in advance.

To do a grep one line at a time would be to read line by line, e.g using a loop. P:S . please dont post in AIX something not OS specifc, threat will. When used on a specific file, grep only outputs the lines that contain the matching string. When run in recursive mode, grep outputs the full path. The grep output will also include the file name in front of the line that matched the specific pattern as shown below. When the Linux shell sees.

I think the best way is to use grep in combination with cut and tail. First, use grep to get the line on which the desired string is (-n to output line. Learn how to use the Grep command to search one or more Unix or Linux files for consider using it to generate a list of source code lines that contain a certain. Use two greps: grep '^FORMUL' *pdb | grep -vE 'C([]|[12][])'. The first lists the lines matching ^FORMUL, the second removes (-v inverts. Beginning at the first line in the file, grep copies a line into a way you could track down a particular string more easily, if you needed to open .. There is much more you can do with sed – see for a nice.